=INDEX(B1:C4,2,1) gets the value at the intersection of the second row and first column in the range : INDEX « Lookup Reference functions « Microsoft Office Excel 2007 Tutorial

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Microsoft Office Excel 2007 Tutorial » Lookup Reference functions » INDEX 
19.8.2.=INDEX(B1:C4,2,1) gets the value at the intersection of the second row and first column in the range
Input the formula: =INDEX(B1:C4,2,1). Press Enter to get the result.
Input the formula: =INDEX(B1:C4,2,1)
19.8.INDEX
19.8.1.INDEX Uses an index to choose a value from a reference or arrayINDEX Uses an index to choose a value from a reference or array
19.8.2.=INDEX(B1:C4,2,1) gets the value at the intersection of the second row and first column in the range=INDEX(B1:C4,2,1) gets the value at the intersection of the second row and first column in the range
19.8.3.=INDEX({1,2;3,4},0,2) returns the value in the first row, second column in the array constant=INDEX({1,2;3,4},0,2) returns the value in the first row, second column in the array constant
19.8.4.=INDEX(A2:C6,2,3) gets the intersection of the second row and third column in the range A2:C6=INDEX(A2:C6,2,3) gets the intersection of the second row and third column in the range A2:C6
19.8.5.=INDEX((A1:C6,A8:C11),2,2,2) gets the intersection of the second row and second column in the second area of A8:C11=INDEX((A1:C6,A8:C11),2,2,2) gets the intersection of the second row and second column in the second area of A8:C11
19.8.6.=SUM(INDEX(A1:C11,0,3,1)) returns the sum of the third column in the first area of the range A1:C11=SUM(INDEX(A1:C11,0,3,1)) returns the sum of the third column in the first area of the range A1:C11
19.8.7.=SUM(B2:INDEX(A2:C6,5,2)) sums the range starting at B2 and ends at the intersection of the fifth row and the second column of the range A2:A6=SUM(B2:INDEX(A2:C6,5,2)) sums the range starting at B2 and ends at the intersection of the fifth row and the second column of the range A2:A6
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