Source Code Cross Referenced for Path.java in  » Portal » uPortal_rel-2-6-1-GA » org » jasig » portal » car » Java Source Code / Java DocumentationJava Source Code and Java Documentation

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Java Source Code / Java Documentation » Portal » uPortal_rel 2 6 1 GA » org.jasig.portal.car 
Source Cross Referenced  Class Diagram Java Document (Java Doc) 


001:        /* Copyright 2002 The JA-SIG Collaborative.  All rights reserved.
002:         *  See license distributed with this file and
003:         *  available online at http://www.uportal.org/license.html
004:         */
005:
006:        package org.jasig.portal.car;
007:
008:        import java.io.StringWriter;
009:        import java.io.PrintWriter;
010:        import java.util.Iterator;
011:        import java.util.LinkedList;
012:
013:        /**
014:         Holds onto a set of String path elements to assist with tracking where in
015:         an XML structure SAX processing is currently working. So an XML structure
016:         like the following would have a path of "<top>", "<next>", "<more>" when SAX
017:         processing issued a startElement event call for the "more" element.
018:         <code>
019:         &lt;top>
020:         &lt;next>
021:         &lt;more>
022:         ...
023:         </code>
024:
025:         Use the fromXML method to create from a more visually symbolic view of
026:         what the path represents.
027:         */
028:        public class Path {
029:            public static final String RCS_ID = "@(#) $Header$";
030:            private LinkedList list = new LinkedList();
031:
032:            /**
033:               Create a new empty path.
034:             */
035:            public Path() {
036:            }
037:
038:            private static final int OUT_OF_TAG = 0;
039:            private static final int IN_TAG = 1;
040:
041:            public static Path fromTag(String tagName) {
042:                return fromXML("<" + tagName + ">");
043:            }
044:
045:            /** 
046:                Creates a Path from the XML structured snippet. The following call
047:                would create a path that contained "top", "next", and "more" in that
048:                order.
049:             */
050:            public static Path fromXML(String xmlPath) {
051:                Path path = new Path();
052:
053:                if (xmlPath == null)
054:                    return path;
055:
056:                int state = OUT_OF_TAG;
057:                StringBuffer label = new StringBuffer();
058:
059:                for (int i = 0; i < xmlPath.length(); i++) {
060:                    char c = xmlPath.charAt(i);
061:
062:                    if (state == OUT_OF_TAG) {
063:                        if (c == '<')
064:                            state = IN_TAG;
065:                    } else // in tag
066:                    {
067:                        if (c == '>') {
068:                            state = OUT_OF_TAG;
069:                            path.append(label.toString());
070:                            label.delete(0, label.length());
071:                        } else
072:                            label.append(c);
073:                    }
074:                }
075:                return path;
076:            }
077:
078:            /**
079:               Add an item to the path.
080:             */
081:            public Path append(String item) {
082:                if (item != null)
083:                    list.add(item);
084:                return this ;
085:            }
086:
087:            /**
088:               Remove the last item off of the path.
089:             */
090:            public String removeLast() {
091:                if (list.size() > 0)
092:                    return (String) list.removeLast();
093:                return null;
094:            }
095:
096:            /**
097:               Returns true if the passed in object is a path with the same number of
098:               path items and all strings in the two paths are equal.
099:             */
100:            public boolean equals(Object o) {
101:                if (!(o instanceof  Path))
102:                    return false;
103:
104:                return list.equals(((Path) o).list);
105:            }
106:
107:            public String toString() {
108:                StringWriter sw = new StringWriter();
109:                PrintWriter pw = new PrintWriter(sw);
110:
111:                for (Iterator i = list.iterator(); i.hasNext();)
112:                    pw.print("<" + i.next() + ">");
113:                pw.flush();
114:                return sw.toString();
115:            }
116:        }
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