\s*: matches zero or one white-space character. : Regular Expressions « Development « VB.Net

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VB.Net » Development » Regular ExpressionsScreenshots 
\s*: matches zero or one white-space character.
  

Imports System.Text.RegularExpressions

Module Example
   Public Sub Main()
      Dim pattern As String = "\b(\S+)\s*"
      Dim input As String = "This is the first sentence of the first paragraph. " + _
                            "This is the second sentence." + vbCrLf + _
                            "This is the only sentence of the second paragraph."
      For Each match As Match In Regex.Matches(input, pattern)
         Console.WriteLine(match.Groups(1))
      Next
   End Sub
End Module

   
    
  
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23.\w matches any word character.
24.(\w) matches a word character. This is the first capturing group.
25.\1 match the value of the first capture.
26.\s matches any white-space character.
27.\b: Begin the match at a word boundary.
28.\w+: Match one or more word characters.
29.(e)*: Match an "e" either zero or one time.
30.(\s|$) Match either a whitespace character or the end of the input string.
31.^: Begin the match at the beginning of the input string.
32.\D: Match a non-digit character.
33.\d{1,5} Matches from one to five decimal digits.
34.\D* matches zero or one non-decimal character.
35.$ Matches the end of the input string.
36.\S matches any non-white-space character.
37.\b: Begin the match at a word boundary.
38.(\S+): matches one or more non-white-space characters. This is the first capturing group.
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